A) \[{{I}_{2}}+10HN{{O}_{3}}\xrightarrow{{}}2HI{{O}_{3}}+10N{{O}_{2}}+4{{H}_{2}}O\]
B) \[3Cu+8HN{{O}_{3}}\xrightarrow{{}}3Cu{{(N{{O}_{3}})}_{2}}\] \[+\,2NO+4{{H}_{2}}O\]
C) \[4Zn+10HN{{O}_{3}}\xrightarrow{{}}4Zn{{(N{{O}_{3}})}_{2}}\] \[+\,N{{H}_{4}}N{{O}_{3}}+3{{H}_{2}}O\]
D) \[2HN{{O}_{3}}+{{P}_{2}}{{O}_{5}}\xrightarrow{{}}2HP{{O}_{3}}+{{N}_{2}}{{O}_{5}}\]
Correct Answer: D
Solution :
[a] \[{{\text{I}}_{\text{2}}}\text{+}\,\text{10}\overset{\text{+}\,\text{5}}{\mathop{\text{HN}}}\,{{\text{O}}_{\text{3}}}\xrightarrow{{}}\] \[2HI{{O}_{3}}+10\overset{+2}{\mathop{NO}}\,\,+\,4{{H}_{2}}O\] In the reaction \[\text{HN}{{\text{O}}_{\text{3}}}\]is acting as oxidizing agent because i|Ls oxidation state is decreasing from + 5 to + 2. [b] \[\text{3Cu}\,\text{+}\,\text{8}\overset{\text{+5}}{\mathop{\text{HN}}}\,{{\text{O}}_{\text{3}}}\xrightarrow{{}}\] \[3Cu{{(N{{O}_{3}})}_{2}}+2\overset{+2}{\mathop{NO}}\,+4{{H}_{2}}O\] It is reaction in which \[\text{HN}{{\text{O}}_{\text{3}}}\]is acting as oxidising agent because oxidation number of nitrogen is decreasing. [c] \[4Zn+10\overset{+5}{\mathop{HN}}\,{{O}_{3}}\xrightarrow{{}}4Zn{{(N{{O}_{3}})}_{2}}\] \[+\,N{{H}_{4}}\,{{\overset{+2}{\mathop{NO}}\,}_{3}}\,+3{{H}_{2}}O\] \[\therefore \]It is also a reaction, in which \[\text{HN}{{\text{O}}_{\text{3}}}\]is oxidizing agent. [d] \[2HN{{O}_{3}}+{{P}_{2}}{{O}_{5}}\xrightarrow[{}]{{}}2HP{{O}_{3}}+{{N}_{2}}{{O}_{5}}\]\[{{P}_{2}}{{O}_{5}}\] dehydrating agent. So in this reaction \[\text{HN}{{\text{O}}_{\text{3}}}\]does not act as oxidizing agent.
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