JCECE Medical JCECE Medical Solved Paper-2006

  • question_answer
    If\[f\] is the frequency when mass m is attached to a spring of spring constant\[k,\]then new frequency for this arrangement, is:

    A) \[f/2\]

    B)  \[\sqrt{2f}\]

    C)  \[f/\sqrt{2}\]

    D)  \[2\sqrt{2f}\]

    Correct Answer: B

    Solution :

     Key Idea: The system executes SHM. The frequency of oscillation of spring mass system is given by \[f=\frac{1}{2\pi }\sqrt{\frac{k}{m}}\] For the given arrangement \[k={{k}_{1}}+{{k}_{2}}=k+k=2k\] Hence, frequency of oscillation is \[f=\frac{1}{2\pi }\sqrt{\frac{k}{m}}\] \[\Rightarrow \] \[f=\frac{1}{2\pi }\sqrt{\frac{2k}{m}}=\sqrt{2}f\]


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