JCECE Medical JCECE Medical Solved Paper-2006

  • question_answer
    A nucleus \[_{\text{Z}}^{\text{A}}\text{X}\]emits one \[\alpha \]and \[2\beta \] particles, then final nucleus is:

    A) \[Y_{Z}^{A}-2\]

    B)  \[Y_{Z-4}^{A-4}\]

    C)  \[Y_{Z}^{A-4}\]

    D)  \[X_{Z}^{A}\]

    Correct Answer: C

    Solution :

     Key Idea: \[\beta -\]particles are fast moving electrons. When\[\alpha -\]particle is emitted by an atom, its atomic number decreases by 2 and mass number by 4. \[\therefore \] \[_{Z}^{A}X\xrightarrow{\alpha }_{Z-2}^{A-4}M\] When \[\beta -\]particle is emitted, the atomic number increases by 1, while mass number remains unchanged, therefore \[_{Z-2}^{A-4}M\xrightarrow{2\beta }_{\,\,\,\,\,\,Z}^{A-4}Y\]


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