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JCECE Medical JCECE Medical Solved Paper-2006

  • question_answer
    The first overtone frequency of a wave on string of length 2 m is 250 Hz. Then, its velocity is:

    A)  1000 m/s     

    B)  25 m/s

    C)  500 m/s      

    D)  10 m/s

    Correct Answer: C

    Solution :

     The first overtone of a wave on string is given by \[n=\frac{v}{\lambda }\] where\[\lambda \] is wavelength, \[v\]the velocity and \[n\]the frequency. Given, \[\lambda =l\](in first overtone) \[\therefore \] \[n=\frac{v}{l}\] \[\Rightarrow \] \[v=nl=250\times 2=500\,m/s.\]


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