A) glucose
B) fructose
C) sucrose
D) all of these
Correct Answer: A
Solution :
Glucose reduces Fehling solution to give red ppt. of \[\text{C}{{\text{u}}_{\text{2}}}\text{O}\]as: \[{{(\underset{C{{H}_{2}}OH}{\overset{CHO}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,HOH)}_{4}}+\underset{\begin{smallmatrix} \text{Fehling} \\ \text{solution} \end{smallmatrix}}{\mathop{2Cu{{(OH)}_{2}}}}\,+NaOH\xrightarrow{{}}\] \[\underset{\text{red}\,\text{ppt}\text{.}}{\mathop{C{{u}_{2}}O}}\,+{{(\underset{C{{H}_{2}}OH}{\overset{COONa}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,HOH)}_{4}}+3{{H}_{2}}O\] Fructose and sucrose does not respond to Fehling solution.
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