JCECE Medical JCECE Medical Solved Paper-2007

  • question_answer
    For sky wave propagation of 10 MHz signal, what should be the minimum electron density in ionosphere?

    A)  \[\tilde{\ }1.2\times {{10}^{12}}{{m}^{-3}}\]

    B)  \[\tilde{\ }{{10}^{6}}\,{{m}^{-3}}\]

    C)  \[\tilde{\ }{{10}^{14}}\,{{m}^{-3}}\]

    D)  \[\tilde{\ }{{10}^{22}}\,{{m}^{-3}}\]

    Correct Answer: A

    Solution :

     The critical frequency of sky wave undergoing reflection from a layer of atmosphere is \[{{f}_{c}}=\sqrt[9]{{{N}_{\max }}}\] where N is electron density per \[{{m}^{3}}.\] \[\therefore \] \[{{N}_{\max }}=\frac{{{f}_{c}}^{2}}{81}=\frac{{{(10\times {{10}^{6}})}^{2}}}{81}\] \[=1.2\times {{10}^{12}}\,{{m}^{-3}}\]


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