A) angle between \[\text{\vec{v}}\]and \[\text{\vec{B},}\] is necessarily \[90{}^\circ \]
B) angle between\[\text{\vec{v}}\]and\[\text{\vec{B},}\]can have any value other than \[\text{9}{{\text{0}}^{o}}\]
C) angle between\[\text{\vec{v}}\]and \[\text{\vec{B},}\]can have any value other than zero and \[{{180}^{o}}\]
D) angle between \[\text{\vec{v}}\]and \[\text{\vec{B},}\]is either zero or \[{{180}^{o}}\]
Correct Answer: C
Solution :
When a charged particle q is moving in a uniform magnetic field\[\text{\vec{B}}\] with velocity \[\text{\vec{v}}\]Such that angle between\[\text{\vec{v}}\]and \[\text{\vec{B}}\] be \[\,\theta ,\] then due to interaction between the magnetic field produced due to moving charge and magnetic force applied, the charge q experiences a force which is given by \[F=qvB\sin \theta \] If \[\theta ={{0}^{o}}\]or \[{{180}^{o}},\]then \[\sin \theta =0\] \[\therefore \] \[F=qvB\sin \theta =0\] Since, force on charged particle is non-zero, so angle between\[\text{\vec{v}}\]and \[\text{\vec{B}}\] can have any value other than zero and \[\text{18}{{\text{0}}^{\text{o}}}\text{.}\] Note: Force experienced by the charged particle is Lorentz force.
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