A) 22 dyne
B) 20 N
C) 20 dyne
D) 100 N
Correct Answer: B
Solution :
The accelerating force on the rocket = upward thrust \[=\frac{\Delta m}{\Delta t}.u\] Given, \[\frac{\Delta m}{\Delta t}=50\times {{10}^{-3}}kg/s,\,v=400\,m/s\] So, accelerating force \[=50\times {{10}^{-3}}\times 400\] \[=20\text{ }N\]
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