A) \[{{K}_{c}}=\frac{[{{P}_{4}}{{O}_{10}}]}{[{{P}_{4}}]{{[{{O}_{2}}]}^{5}}}\]
B) \[{{K}_{c}}=\frac{[{{P}_{4}}{{O}_{10}}]}{5[{{P}_{4}}][{{O}_{2}}]}\]
C) \[{{K}_{c}}={{[{{O}_{2}}]}^{5}}\]
D) \[{{K}_{c}}=\frac{1}{{{[{{O}_{2}}]}^{5}}}\]
Correct Answer: D
Solution :
In the expression for equilibrium constant (\[{{K}_{p}}\]or\[{{K}_{c}}\]) species in solid state are not written (ie, their molar concentrations are taken as 1) \[{{P}_{4}}(s)+5{{O}_{2}}{{P}_{4}}{{O}_{10}}(s)\] Thus, \[{{K}_{c}}=\frac{1}{{{[{{O}_{2}}]}^{5}}}\]
You need to login to perform this action.
You will be redirected in
3 sec
