A) \[\text{C}{{\text{u}}_{\text{2}}}{{\text{I}}_{\text{2}}}\] is formed
B) \[\text{Cu}{{\text{I}}_{2}}\] is formed
C) \[\text{N}{{\text{a}}_{\text{2}}}{{\text{S}}_{\text{2}}}{{\text{O}}_{\text{3}}}\]is oxidised
D) Evolved \[{{\text{I}}_{2}}\] is reduced
Correct Answer: B
Solution :
\[CuS{{O}_{4}}+2KI\xrightarrow{{}}\underset{\text{unstable}}{\mathop{Cu{{I}_{2}}}}\,+{{K}_{2}}S{{O}_{4}}\] \[2Cu{{I}_{2}}\xrightarrow{{}}C{{u}_{2}}{{I}_{2}}+{{I}_{2}}\] Thus, \[\text{Cu}{{\text{I}}_{\text{2}}}\]is not formed.
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