A) \[~-41\,\text{kJ}\,\text{mo}{{\text{l}}^{-1}}\]
B) \[-1312\text{ kJ mo}{{\text{l}}^{-1}}\]
C) \[-164\text{ kJ mo}{{\text{l}}^{-1}}\]
D) \[~-82\text{ kJ mo}{{\text{l}}^{-1}}\]
Correct Answer: D
Solution :
The energy of second Bohr orbit of hydrogen atom \[({{E}_{2}})\] is \[-328\text{ kJ mo}{{\text{l}}^{-1}}\] because \[{{E}_{2}}=-\frac{1312}{{{2}^{2}}}\,\text{kJ}\,\text{mo}{{\text{l}}^{-}}\] \[\therefore \] \[{{E}_{n}}=-\frac{1312}{{{n}^{2}}}\,\text{kJ}\,\text{mo}{{\text{l}}^{-}}\] If \[n=4\] \[\therefore \] \[{{E}_{4}}=-\frac{1312}{{{4}^{2}}}\text{kJ}\,\text{mo}{{\text{l}}^{-1}}\] \[=-82\,\text{kJ}\,\text{mo}{{\text{l}}^{-1}}\]
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