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JCECE Medical JCECE Medical Solved Paper-2009

  • question_answer
    The equation of a simple harmonic wave is  given by \[y=5\sin \frac{\pi }{2}(100t-x),\]where \[x\]and \[y\]are in metre and time is in second. The period of the wave in second will be

    A)  0.04

    B)  0.01

    C)  1                  

    D)  5

    Correct Answer: A

    Solution :

     The given equation is \[y=5\sin \frac{\pi }{2}(100t-x)\] ?(i) Comparing Eq. (i) with standard wave equation, given by               \[y=A\sin (\omega t-kx)\] ?(ii) we have \[\omega =\frac{100\pi }{2}=50\pi \] \[\Rightarrow \] \[\frac{2\pi }{T}=50\pi \] \[\Rightarrow \] \[T=\frac{2\pi }{50\pi }=0.04\,s\]


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