JCECE Medical JCECE Medical Solved Paper-2009

  • question_answer
    A solenoid 1.5 m long and 0.4 cm in diameter possesses 10 turns per cm length. A current of 5 A falls through it. The magnetic field at the axis inside the solenoid is

    A)  \[2\pi \times {{10}^{-3}}T\]

    B)  \[2\pi \times {{10}^{-5}}T\]

    C)  \[4\pi \times {{10}^{-2}}T\]

    D)   \[4\pi \times {{10}^{-3}}T\]

    Correct Answer: A

    Solution :

     Magnetic field at the axis inside the solenoid \[B={{\mu }_{0}}ni\] Here, \[n=10\,turns/cm=1000turns/m,i=5A\] \[\therefore \] \[B=4\pi \times {{10}^{-7}}\times 1000\times 5\] \[=2\pi \times {{10}^{-3}}T.\]


You need to login to perform this action.
You will be redirected in 3 sec spinner