JCECE Medical JCECE Medical Solved Paper-2009

  • question_answer
    Which of the following compound is expected to be optically active?

    A) \[{{(C{{H}_{3}})}_{2}}CHCHO\]

    B)  \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}CHO\]

    C)  \[C{{H}_{3}}C{{H}_{2}}CHBrCHO\]

    D)  \[C{{H}_{3}}C{{H}_{2}}CB{{r}_{2}}CHO\]

    Correct Answer: C

    Solution :

     Compounds having asymmetric \[\text{C}-\]atom are optically active, eg, \[C{{H}_{3}}-C{{H}_{2}}-\underset{Br}{\overset{H}{\mathop{\underset{|}{\overset{*|}{\mathop{C}}}\,}}}\,-CHO\] (\[\overset{*}{\mathop{C}}\,=\]asymmetric C-atom) The C-atom whose four valencies are satisfied by four different groups is caller asymmetric \[\text{C}-\]atom.


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