A) the reduction of nitrate to nitric oxide
B) oxidation of nitric oxide to nitrogen dioxide
C) reduction of ferrous sulphate to iron
D) oxidising action of sulphuric acid
Correct Answer: A
Solution :
The brown ring is obtained due to the formation of pentaaquanitrosonium ion. In this reaction reduction of nitrate ion by \[\text{F}{{\text{e}}^{\text{2+}}}\]ion takes places as \[\text{NO}_{3}^{-}+3F{{e}^{2+}}+4{{H}^{+}}\xrightarrow{{}}\] \[NO+3F{{e}^{3+}}+2{{H}_{2}}O\] \[F{{e}^{2+}}+NO+5{{H}_{2}}O\xrightarrow{{}}\underset{\text{brown}\,\text{complex}}{\mathop{{{[Fe{{({{H}_{2}}O)}_{5}}NO]}^{2+}}}}\,\]
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