A) \[{{f}_{o}}=45\,cm\]and \[{{f}_{e}}=-9cm\]
B) \[{{f}_{o}}=-7.2\,cm\]and \[{{f}_{e}}=5\,cm\]
C) \[{{f}_{o}}=50\,cm\]and \[{{f}_{e}}=10\,cm\]
D) \[{{f}_{o}}=30\,cm\]and \[{{f}_{e}}=6\,cm\]
Correct Answer: D
Solution :
In this case \[|m|=\frac{{{f}_{0}}}{{{f}_{e}}}=5\] ?(i) and length of telescope \[={{f}_{o}}+{{f}_{e}}=36\] ?(ii) Solving Eqs. (i) and (ii), we get \[{{f}_{e}}=6\,cm,{{f}_{o}}=30\,cm\]
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