A) \[\frac{1}{3}V\]
B) \[\frac{2}{3}V\]
C) \[\frac{3}{2}V\]
D) \[3V\]
Correct Answer: B
Solution :
Potential inside the sphere will be same as that on its surface ie,\[V={{V}_{surface}}=\frac{q}{10}\text{stat}-\text{volt}\] \[{{V}_{out}}=\frac{q}{15}\text{stat}-\text{volt}\] \[\therefore \] \[\frac{{{V}_{out}}}{V}=\frac{2}{3}\Rightarrow {{V}_{out}}=\frac{2}{3}V\]
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