A) \[N{{H}_{4}}OH-C{{H}_{3}}COOH\]
B) \[HN{{O}_{3}}-N{{H}_{4}}OH\]
C) \[NaOH-C{{H}_{3}}COOH\]
D) \[HCl-NaOH\]
Correct Answer: D
Solution :
Heat of neutralisation of strong acid by strong base is always greater than the heat of neutralisation of weak acid or weak base because some energy is used to ionise weat acid or weak base. [a]\[N{{H}_{4}}OH-C{{H}_{3}}COOH\] weak base-weak acid [b]\[~HN{{O}_{3}}N{{H}_{4}}OH\] strong acid-weak base [c]\[~NaOHC{{H}_{3}}COOH\] strong base-weak acid [d]\[HClNaOH\] strong acid-strong base \[\because \] \[\text{HCl}\]is a strong add and NaOH is a strong base. \[\therefore \]Their heat of neutralisation will be highest among the given.
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