A) \[-\Delta G=\Delta H-T\Delta S\]
B) \[\Delta H=\Delta G-T\Delta S\]
C) \[\Delta S=\frac{1}{T}[\Delta G-\Delta H]\]
D) \[\Delta S=\frac{1}{T}[\Delta H-\Delta G]\]
Correct Answer: D
Solution :
We know that, Gibbs for energy change, \[\Delta G=\Delta H-T\Delta S\] \[T\Delta S=\Delta H-\Delta G\] \[\Delta S=\frac{1}{T}[\Delta \Eta -\Delta G]\]
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