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JCECE Medical JCECE Medical Solved Paper-2011

  • question_answer
    The magnifying power of an astronomical telescope is 8 and the distance between the two lenses is 54 cm. The focal length of eye lens and objective lens will be respectively

    A)  6 cm and 48 cm  

    B)  48 cm and 6 cm

    C)  8 cm and 64 cm   

    D)  6 cm and 60 cm

    Correct Answer: A

    Solution :

    \[L={{f}_{0}}+{{f}_{e}}=54\,cm\] \[|m|=\frac{{{f}_{o}}}{{{f}_{e}}}=8\] On simplification, we get \[{{f}_{e}}=+\,6\,cm\] and \[{{f}_{o}}=+\,48\,cm\]


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