JCECE Medical JCECE Medical Solved Paper-2011

  • question_answer
    Power supplied to a particle of mass 2 kg varies with time as \[P=\frac{3{{t}^{2}}}{2}W.\]Here t is in second. If velocity of particle at \[t=0\]is \[v=0,\]the velocity of particle at time \[t=2\,s\]will be

    A)  1 m/s

    B)  4 m/s

    C)  2 m/s

    D)  \[2\sqrt{2}\,m/s\]

    Correct Answer: C

    Solution :

     From work energy theorem \[\Delta \Kappa \Epsilon =W{{E}_{net}}\] or \[{{K}_{f}}-{{K}_{i}}=\int_{{}}^{{}}{p\,dt}\] \[\frac{1}{2}m{{v}^{2}}-0=\int_{0}^{2}{\left( \frac{3}{2}{{t}^{2}} \right)}\,dt\] \[{{v}^{2}}=\left[ \frac{{{t}^{3}}}{2} \right]_{0}^{2}\] \[v=2m/s\]


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