A) \[HN_{3}^{-}\]
B) \[N_{2}^{-}\]
C) \[N_{3}^{-}\]
D) \[{{N}^{3-}}\]
Correct Answer: C
Solution :
Hydrazoicaeidis\[{{N}_{3}}H.\] \[\underset{acid}{\mathop{{{N}_{3}}H}}\,\xrightarrow{{}}\underset{\text{conjugate}\,\text{base}}{\mathop{N_{3}^{-}}}\,+\underset{\text{proton}}{\mathop{{{H}^{+}}}}\,\]
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