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JCECE Medical JCECE Medical Solved Paper-2011

  • question_answer
    250 mL of a sodium carbonate solution contains 2.65 g of \[\text{N}{{\text{a}}_{\text{2}}}\text{C}{{\text{O}}_{\text{3}}}\text{.}\]If 10 mL of this solution is diluted to 1 L, what is the concentration of the resultant solution? (Mol. wt. of\[\text{N}{{\text{a}}_{\text{2}}}\text{C}{{\text{O}}_{\text{3}}}\text{=106}\])

    A)  0.1 M

    B)  0.001 M

    C)  0.01 M

    D)  \[{{10}^{-4}}\,M\]

    Correct Answer: B

    Solution :

     Molarity of \[\text{N}{{\text{a}}_{\text{2}}}\text{C}{{\text{O}}_{\text{3}}}\]solution \[=\frac{2.65}{106}\times \frac{1}{250}\times 1000=0.1\,M\] \[{{M}_{1}}{{V}_{1}}={{M}_{2}}{{V}_{2}}\] \[10\times 0.1=1000\times {{M}_{2}}\] \[\therefore \] \[{{M}_{2}}=\frac{10\times 0.1}{1000}=0.001\,M\]


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