A) Zero
B) 1.25 cm
C) 2.5 cm
D) 5cm
Correct Answer: C
Solution :
Kinetic energy of mass of 10 g is converted into potential energy of the system \[\therefore \] \[\frac{1}{2}{{m}_{1}}v_{1}^{2}=({{m}_{1}}+{{m}_{2}})gh\] or \[h=\frac{{{m}_{1}}v_{1}^{2}}{2({{m}_{1}}+{{m}_{2}})g}\] \[=\frac{10\times {{(100)}^{2}}}{2(10+10)\times 1000}=\frac{10\times 10000}{2\times 20\times 1000}\] \[=\frac{10}{4}=2.5\,cm\]
You need to login to perform this action.
You will be redirected in
3 sec
