JCECE Medical JCECE Medical Solved Paper-2012

  • question_answer
    If a vector A having a magnitude of 8 is added to a vector B which lies along \[x-\]axis, then the resultant of two vectors lies along y-axis and has magnitude twice that of B. The magnitude of B is

    A) \[\frac{6}{\sqrt{5}}\]

    B)  \[\frac{12}{\sqrt{5}}\]

    C)  \[\frac{16}{\sqrt{5}}\]

    D)  \[\frac{8}{\sqrt{5}}\]

    Correct Answer: D

    Solution :

     According to condition, \[A+Bi=Rj\](where, R is the resultant vector) Also,            R=2B \[\therefore \] \[A+Bi=2Bj\] or \[A=2Bj-Bi\] \[\therefore \] \[{{A}^{2}}=4{{B}^{2}}+{{B}^{2}}=5{{B}^{2}}\] Here, \[A=8\] \[\therefore \] \[64=5{{B}^{2}}\] \[\Rightarrow \] \[B=\sqrt{\frac{64}{5}}=\frac{8}{\sqrt{5}}\]


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