JCECE Medical JCECE Medical Solved Paper-2012

  • question_answer
    A body of density \[{{d}_{1}}\]is counterpoised by Mg of weights of density \[{{d}_{2}}\]in air of density d. Then, the true mass of the body is

    A)  M

    B)  \[\frac{M(1-d/{{d}_{2}})}{(1-d/{{d}_{1}})}\]

    C)  \[M\left( 1-\frac{d}{{{d}_{2}}} \right)\]

    D)  \[M\left( 1-\frac{d}{{{d}_{1}}} \right)\]

    Correct Answer: B

    Solution :

     Let\[{{M}_{0}}=\] mass of body in vacuum Apparent weight of body in air = Apparent weight of standard weights in air \[\Rightarrow \]Actual weight - upthrust due to displaced air  = Actual weight - upthrust due to displaced air\[\Rightarrow \] \[{{M}_{0}}g-\left( \frac{{{M}_{0}}}{{{d}_{1}}} \right)dg=Mg-\left( \frac{M}{{{d}_{2}}} \right)dg\] \[\Rightarrow \] \[{{M}_{0}}=\frac{M\left( 1-\frac{d}{{{d}_{2}}} \right)}{1-\frac{d}{{{d}_{1}}}}\]


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