A) 300 min
B) 360 min
C) 398.8 min
D) 400 min
Correct Answer: B
Solution :
\[t=\frac{2.303}{k}\log \frac{a}{a-x}\] (I) When \[a=100,\] \[x=50\]and \[t=120\,\min \] \[k=\frac{2.303}{120}\log \frac{100}{100-50}\] \[k=\frac{2.303}{120}\log 2\] \[k=\frac{2.303\times 0.3010}{120}=0.00578{{\min }^{-1}}\] (II) When \[a=100,x=90,\,\,t=?\] \[t=\frac{2.303}{0.00578}\log \frac{100}{100-90}\] \[t=\frac{2.303}{0.00578}\times \log 10\] \[=398.4\] \[\approx 398.8\,\min \]
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