A) 12.87 J
B) 6.43 J
C) 8.57 J
D) 2.92 J
Correct Answer: D
Solution :
\[{{W}_{rev}}=-2.303nRT\log \frac{{{V}_{2}}}{{{V}_{1}}}\] \[=-2.303\times 1\times 0.0821\] \[\times \,(273+37)log\frac{25}{15}\] \[=-2.303\times 0.0821\times 310\log \frac{5}{3}\] \[=-13J=-12.87\,J\]
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