A) \[\text{1 cal/s}\]
B) \[\text{2 cal/s}\]
C) \[\text{3 cal/s}\]
D) \[\text{4 cal/s}\]
Correct Answer: C
Solution :
Given, heat produced per second in \[5\,\Omega \] Resistor \[=10\,cal/s=10\times 4.2\,J/s\] So, \[\frac{{{V}^{2}}}{5}=10\times 4.2\] or \[V=\sqrt{10\times 4.2\times 5\,V}\] \[=\sqrt{42\times 5\,V}\] Potential difference across A and \[B=\sqrt{42\times 5}\] So, current in\[6\Omega ,\] \[l=\frac{\sqrt{42\times 5}}{10}\text{ampere}\] Hence, heat produced in it, \[H={{\left( \frac{\sqrt{42\times 5}}{10} \right)}^{2}}\times \,\,J/s\] \[=\frac{42\times 5}{100}\times \frac{6}{4.2}\] \[=3\,cal/s\]
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