JCECE Medical JCECE Medical Solved Paper-2013

  • question_answer
    \[C{{H}_{3}}-C=CH\xrightarrow[1%\,HgS{{O}_{4}}]{40%\,{{H}_{2}}S{{O}_{4}}}A\xrightarrow{\text{Isomerisation}}\] \[C{{H}_{3}}COC{{H}_{3}}\] Structure of A and the type of isomerism in the above reaction are respectively.

    A)  prop-l-en-2-ol, metamerism

    B)  prop-1-en-l-ol, tautomerism

    C)  prop-2-en-2-ol, cis and trans isomerism

    D)  prop-2-en-1-ol, tautomerism

    Correct Answer: B

    Solution :

     \[C{{H}_{3}}-C=CH\xrightarrow[1%HgS{{O}_{4}}]{40%{{H}_{2}}S{{O}_{4}}}C{{H}_{3}}-\overset{OH}{\mathop{\overset{|}{\mathop{C}}\,}}\,=C{{H}_{2}}\] \[C{{H}_{3}}-C=CH\xrightarrow[1%HgS{{O}_{4}}]{40%{{H}_{2}}S{{O}_{4}}}\underset{\begin{smallmatrix}  \text{Prop}-1-\text{en}-2-\text{ol} \\  \xrightarrow{\text{Tautomerisation}} \end{smallmatrix}}{\mathop{C{{H}_{3}}-\overset{OH}{\mathop{\overset{|}{\mathop{C}}\,}}\,=C{{H}_{2}}}}\,\] \[C{{H}_{3}}COC{{H}_{3}}\]


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