A) \[0.8g/cc\]
B) \[1.2g/cc\]
C) \[1.4g/cc\]
D) \[1.6g/cc\]
Correct Answer: A
Solution :
Its shown in figure, in the two arms of a tube pressure remains same on surface pp. Hence, \[8\times {{p}_{y}}\times g+2\times {{\rho }_{Hg}}=10\times {{\rho }_{x}}\times g\] \[8\times {{\rho }_{y}}+2\times 13.6=10\times 3.36\] \[{{\rho }_{y}}=\frac{33.6-272}{8}=0.8g/cc\]
You need to login to perform this action.
You will be redirected in
3 sec
