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JCECE Medical JCECE Medical Solved Paper-2014

  • question_answer
    U is the PE of an oscillating particle and F is the force acting on it at a given instant. Which of the following is true?

    A) \[\frac{U}{F}+x=0\]

    B)  \[\frac{2U}{F}+x=0\]

    C)  \[\frac{F}{U}+x=0\]

    D)  \[\frac{F}{2U}+x=0\]

    Correct Answer: B

    Solution :

     Potential energy of an oscillating particle \[U=\frac{1}{2}k{{x}^{2}}\] \[2U=k{{x}^{2}}\] \[2U=-kx\] \[\frac{2U}{F}=-x\] or \[\frac{2U}{F}+x=0\]


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