A) \[LiCl>KCl>NaCl>CsCl\]
B) \[CsCl>KCl>NaCl>LiCl\]
C) \[NaCl>KCl>LiCl>CsCl\]
D) \[KCl>CsCl>NaCl>LiCl\]
Correct Answer: D
Solution :
Stability of a compound depends upon its enthalpy of formation \[\Delta {{h}_{f}}.\]The more negative value of \[\Delta {{H}_{f}}\]shows more stability of a compound. Thus, KCI is more stable and \[\text{LiCl}\]is least stable. \[\Delta {{\Eta }_{f}}\]for \[LiCl=-408.8\,kJ\,mo{{l}^{-1}}\] \[\Delta {{\Eta }_{f}}\]for \[NaCl=-412.5\,kJ\,mo{{l}^{-1}}\] \[\Delta {{\Eta }_{f}}\]for \[CsCl=-433\,kJ\,mo{{l}^{-1}}\] \[\Delta {{\Eta }_{f}}\]for \[KCl=-436\,kJ\,mo{{l}^{-1}}\]
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