| (i) Colour of a transition metal complex is dependent on energy difference, between two d-levels. |
| (ii) Colour of the complex is dependent on the nature of the ligand and the type of complex formed. |
| (iii) \[\text{ZnS}{{\text{O}}_{\text{4}}}\]and \[\text{Ti}{{\text{O}}_{\text{2}}}\]are white as in both, d-d spectra are impossible. |
A) I, If and III
B) I and II
C) II and III
D) I and III
Correct Answer: A
Solution :
Colour of transition metal complex is dependent on energy difference between \[{{t}_{2g}}\]and \[{{e}_{g}}\]sets of d-orbitals, nature of ligand and type of complex formed, d-d transition is possible in \[{{d}^{1}}\]and \[{{d}^{9}}\]ions. That is why such ion complexes are coloured. On the other hand, \[{{d}^{0}}\]and \[{{d}^{0}}\]ions (such of \[Z{{n}^{2+}},T{{i}^{4+}}\]cannot show d-d transition, hence colourless.
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