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JCECE Medical JCECE Medical Solved Paper-2014

  • question_answer
    For the reaction, \[Zn(s)+C{{u}^{2+}}(0.1\,M)\xrightarrow{{}}Z{{n}^{2+}}(1M)+Cu(s)t\] aking place in a cell;\[E_{cell}^{o}\] is\[1.10\,V.{{E}_{cell}}\] for the cell will be \[\left( 2.303\frac{RT}{F}=0.0591 \right)\]

    A) \[~1.80\,V\]             

    B) \[~1.07\,V\]

    C) \[0.82\,V\]             

    D) \[2.14\,V\]

    Correct Answer: B

    Solution :

     \[{{E}_{cell}}=E_{cell}^{o}-\frac{0.0591}{n}\log \left( \frac{Z{{n}^{2+}}}{C{{u}^{2+}}} \right)\] \[=1.10-\frac{0.0591}{2}\log \frac{1}{0.1}\] \[=1.07\,V\]


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