A) \[\underset{(4-\text{methyl}-1-\text{pentanal})}{\mathop{C{{H}_{3}}-\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{CH}}\,}}\,-C{{H}_{2}}-C{{H}_{2}}-CHO}}\,\]
B) \[\underset{(4-\text{methyl}-2-\text{pentyn}-1-\text{oic}\,\text{acid})}{\mathop{C{{H}_{3}}-\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{CH}}\,}}\,-C\equiv C-COOH}}\,\]
C) \[\underset{(2-\text{methyl}-1-\text{pentynoic acid})}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}-\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{CH}}\,}}\,-COOH}}\,\]
D) \[\underset{(3-hexen-5-one)}{\mathop{C{{H}_{3}}C{{H}_{2}}-CH=CH-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-C{{H}_{3}}}}\,\]
Correct Answer: D
Solution :
\[\underset{3-\text{hexen}-2-\text{one}}{\mathop{\overset{6}{\mathop{C}}\,{{H}_{3}}-\overset{5}{\mathop{C}}\,{{H}_{2}}-\overset{4}{\mathop{C}}\,H}}\,=\overset{3}{\mathop{C}}\,H-\overset{\text{O}}{\mathop{\overset{||}{\mathop{^{2}C}}\,}}\,-\overset{1}{\mathop{C}}\,{{H}_{3}}\]
You need to login to perform this action.
You will be redirected in
3 sec
