JCECE Medical JCECE Medical Solved Paper-2015

  • question_answer
    The difference of water molecules in gypsum and plaster of Paris is

    A) \[\frac{5}{2}\]

    B)  2

    C)  \[\frac{1}{2}\]

    D)  \[1\frac{1}{2}\]

    Correct Answer: D

    Solution :

     Formula of gypsum \[=CaS{{O}_{4}}.2{{H}_{2}}O\] Formula of plaster of Paris \[=CaS{{O}_{4}}.\frac{1}{2}{{H}_{2}}O\] Thus, difference of water molecule \[=2{{H}_{2}}O-\frac{1}{2}{{H}_{2}}O=1\frac{1}{2}{{H}_{2}}O\]


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