A) \[4+2\sqrt{3}\]
B) \[-2-\sqrt{3}\]
C) \[-2+\sqrt{3}\]
D) \[-4-2\sqrt{3}\]
Correct Answer: B
Solution :
\[0(0-cosx)-cosx(0-co{{s}^{2}}x)-sinx\]\[(si{{n}^{2}}x-0)=0\]\[{{\cos }^{3}}x-{{\sin }^{3}}x=0\]\[{{\tan }^{3}}=1\Rightarrow \tan x=1\] \[\sum\limits_{{}}^{{}}{\frac{\sqrt{3}+\tan x}{1-\sqrt{3}}}\] \[\sum\limits_{{}}^{{}}{\frac{\sqrt{3}+1}{1-\sqrt{3}}\times \frac{1+\sqrt{3}}{1+\sqrt{3}}}\Rightarrow \sum\limits_{{}}^{{}}{\frac{1+3+2\sqrt{3}}{-2}=}\sum\limits_{{}}^{{}}{\frac{{{4}^{2}}}{-2}-\frac{2\sqrt{3}}{3}}\]\[\sum\limits_{{}}^{{}}{-2-\sqrt{3}}\]
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