JEE Main & Advanced JEE Main Paper (Held On 8 April 2017)

  • question_answer
    Let \[f(x)={{2}^{10}}dx+1\]and\[g(x)={{3}^{10}}x-1.\]If\[(fog)(x)=x,\]then x is equal to: [JEE Online 08-04-2017]

    A) \[\frac{{{2}^{10}}-1}{{{2}^{10}}-{{3}^{-10}}}\]                     

    B) \[\frac{1-{{2}^{-10}}}{{{3}^{10}}-{{2}^{-10}}}\]

    C) \[\frac{{{3}^{10}}-1}{{{3}^{10}}-{{2}^{-10}}}\]                     

    D) \[\frac{1-{{3}^{-10}}}{{{2}^{10}}-{{3}^{-10}}}\]

    Correct Answer: B

    Solution :

                    \[f(g(x))=x\]                 \[f({{3}^{10}}x-1)={{2}^{10}}({{3}^{10}}.x-1)=x\]                 \[=\frac{1}{{{3}^{10}}-{{2}^{-110}}}\]                 \[{{2}^{10}}({{3}^{10}}x-1)+1=x\]                 \[x({{6}^{10}}-1)={{2}^{10}}-1\] \[x=\frac{{{2}^{10}}-1}{{{6}^{10}}-1}=\frac{1-{{2}^{-10}}}{{{3}^{10}}-{{2}^{-10}}}\]


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