JEE Main & Advanced JEE Main Paper (Held On 8 April 2017)

  • question_answer
    The integral\[\int_{{}}^{{}}{\sqrt{1+2\cot x(cosecx+cotx)}dx}\]\[\left( 0<x<\frac{x}{2} \right)\]is equal to :  (where C is a constant of integration ) [JEE Online 08-04-2017]

    A) \[2\log \left( \sin \frac{x}{2} \right)+C\]

    B) \[4\log \left( \sin \frac{x}{2} \right)+C\]

    C) \[4\log \left( \cos \frac{x}{2} \right)+C\]               

    D) \[2\log \left( \cos \frac{x}{2} \right)+C\]

    Correct Answer: A

    Solution :

    \[\int_{{}}^{{}}{\left( \sqrt{+2\cot x\cos ecx+\cos e{{c}^{2}}x+\cot x} \right)dx}\]                 \[\int_{{}}^{{}}{\cos |x+\cot x|dx}\]                 \[\int_{{}}^{{}}{(cosec+cotx)dx}\]                 \[\int_{{}}^{{}}{\cos ec\,dx}\]                 \[2\log (log({{x}_{2}})+c\]


You need to login to perform this action.
You will be redirected in 3 sec spinner