A) \[0.63\times {{10}^{-3}}rad/s\]
B) \[0.28\times {{10}^{-3}}rad/s\]
C) \[1.1\times {{10}^{-3}}rad/s\]
D) \[0.83\times {{10}^{-3}}rad/s\]
Correct Answer: A
Solution :
\[g'=g-{{\omega }^{2}}R{{\cos }^{2}}\theta \] \[\frac{3g}{4}=g-{{\omega }^{2}}R\] \[{{w}^{2}}R=\frac{g}{4}\] \[w=\sqrt{\frac{g}{4R}}\] \[=\sqrt{\frac{10}{4\times 64\omega \times {{10}^{3}}}}\] \[=\frac{1}{2\times 8\times 100}\] \[=\frac{1}{1600}=\frac{1}{16}\times {{10}^{-2}}=0.6\times {{10}^{-3}}\]
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