JEE Main & Advanced JEE Main Paper (Held On 8 April 2017)

  • question_answer
    In a certain region static electric and magentic fields exist. The magnetic field is given by \[\vec{B}={{B}_{0}}\left( \hat{i}+2\hat{j}-4\hat{k} \right).\]If a test charge moving with a velocity \[\vec{\upsilon }={{\upsilon }_{0}}\left( 3\hat{i}-\hat{j}+2\hat{k} \right)\]experience no force in that region, then the electric field in the region, in SI units, is -                              [JEE Online 08-04-2017]

    A)  \[\vec{E}=-{{\upsilon }_{0}}{{B}_{0}}\left( \hat{i}+\hat{j}+7\hat{k} \right)\]

    B)  \[\vec{E}=-{{\upsilon }_{0}}{{B}_{0}}\left( 3\hat{i}-2\hat{j}-4\hat{k} \right)\]

    C)  \[\vec{E}={{\upsilon }_{0}}{{B}_{0}}\left( 14\hat{i}+7\hat{k} \right)\]

    D)  \[\vec{E}={{\upsilon }_{0}}{{B}_{0}}\left( 14\hat{j}+7\hat{k} \right)\]    

    Correct Answer: D

    Solution :

     \[{{F}_{e}}={{F}_{n}}=0\]                 \[{{F}_{e}}=-{{F}_{m}}\]                 \[=-q\left( \vec{v}\times \vec{B} \right)\]                 \[=-{{\upsilon }_{0}}{{v}_{0}}\left[ \left( 3\hat{i}-\hat{j}+2\hat{k} \right)\times \left( \hat{i}+2\hat{j}-4\hat{k} \right) \right]\]                 \[=-{{\upsilon }_{0}}{{v}_{0}}\left( 14\hat{i}+7\hat{k} \right)\]


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