question_answer

The major product of the following reaction is:  [JEE Online 08-04-2017] \[{{C}_{6}}{{H}_{5}}C{{H}_{2}}-\underset{\begin{smallmatrix}  | \\  Br \end{smallmatrix}}{\overset{\begin{smallmatrix}  C{{H}_{3}} \\  | \end{smallmatrix}}{\mathop{C}}}\,-C{{H}_{2}}-C{{H}_{3}}\xrightarrow[{{C}_{2}}{{H}_{5}}OH]{{{C}_{2}}{{H}_{5}}ONa}\]

A) \[{{C}_{6}}{{H}_{5}}C{{H}_{2}}=\underset{\begin{smallmatrix}  | \\  C{{H}_{3}} \end{smallmatrix}}{\mathop{C}}\,-C{{H}_{2}}C{{H}_{3}}\]

B) \[{{C}_{6}}{{H}_{5}}C{{H}_{2}}-\underset{\begin{smallmatrix}  | \\  C{{H}_{3}} \end{smallmatrix}}{\mathop{C}}\,=CHC{{H}_{3}}\]

C) \[{{C}_{6}}{{H}_{5}}C{{H}_{2}}-\underset{\begin{smallmatrix}  | \\  O{{C}_{2}}{{H}_{5}} \end{smallmatrix}}{\overset{\begin{smallmatrix}  C{{H}_{3}} \\  | \end{smallmatrix}}{\mathop{C}}}\,-C{{H}_{2}}C{{H}_{3}}\]

D) \[{{C}_{6}}{{H}_{5}}C{{H}_{2}}-\underset{\begin{smallmatrix}  | \\  C{{H}_{2}}C{{H}_{3}} \end{smallmatrix}}{\mathop{C}}\,=C{{H}_{2}}\]

Correct Answer: A

Solution :