A) \[HOCl+{{H}_{2}}{{O}_{2}}\to {{H}_{3}}{{O}^{+}}+C{{l}^{-}}+{{O}_{2}}\]
B) \[{{I}_{2}}+{{H}_{2}}{{O}_{2}}+2O{{H}^{-}}\to 2{{I}^{-}}+2{{H}_{2}}O+{{O}_{2}}\]
C) \[PbS+4{{H}_{2}}{{O}_{2}}\to PbS{{O}_{4}}+4{{H}_{2}}O\]
D) \[2MnO_{4}^{-}+3{{H}_{2}}{{O}_{2}}\to 2Mn{{O}_{2}}+3{{O}_{2}}+2{{H}_{2}}O+2O{{H}^{-}}\]
Correct Answer: C
Solution :
\[\underset{+2}{\mathop{PbS+}}\,4{{H}_{2}}{{O}_{2}}\xrightarrow[{}]{{}}\underset{+4}{\mathop{PbS{{O}_{4}}}}\,+4{{H}_{2}}O\]
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