A) 2E
B) E
C) zero
D) None of these
Correct Answer: C
Solution :
From Kirchhoffs second law \[V=\Sigma ir\] (for closed mesh) where\[V\]is potential difference,\[i\]the current and \[r\]the resistance. \[\therefore \] \[E+E=Ir+Ir=2Ir\] or \[I=\frac{E}{r}\] ? (i) \[{{V}_{x}}-{{V}_{y}}=E-Ir\] Putting the value of\[I\]from Eq. (i), we get \[{{V}_{x}}-{{V}_{y}}=E-\frac{E}{r}\times V=0\]
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