A) 20.4V
B) 13.6V
C) 30.6V
D) 40.8V
Correct Answer: B
Solution :
The minimum energy needed to ionize an atom is called ionization energy. The potential difference through which an electron should be accelerated to acquire this much energy is called ionization potential. \[{{({{E}_{2}})}_{H}}-{{({{E}_{1}})}_{H}}=10.2\,\,eV\] or \[\frac{{{({{E}_{1}})}_{H}}}{4}-{{({{E}_{1}})}_{H}}=10.2\,\,eV\] \[\therefore \] \[{{({{E}_{1}})}_{H}}=-13.6\,\,eV\] Hence, ionization potential energy is \[={{({{E}_{\infty }})}_{H}}-{{({{E}_{1}})}_{H}}=13.6\,\,eV\] \[\therefore \] lonisational potential\[=13.6\,\,eV\]
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