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Manipal Engineering Manipal Engineering Solved Paper-2008

  • question_answer
    The radius of\[N{{a}^{+}}\]is\[95\,\,\text{pm}\]and that of\[C{{l}^{-}}\]ion is\[181\,\,\text{pm}\]. The coordination number of\[N{{a}^{+}}\]is

    A)  8                                            

    B)  6

    C)  4                            

    D)         unpredictable

    Correct Answer: B

    Solution :

    \[\frac{{{r}_{+}}}{{{r}_{-}}}=\frac{95}{181}=0.524\] \[\because \]The radius ratio lies between 0.414 to 0.732. \[\therefore \]The coordination number of\[N{{a}^{+}}\]is 6.


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