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Manipal Engineering Manipal Engineering Solved Paper-2008

  • question_answer
    The standard reduction potentials at\[298K\]for the following half-cell reactions are given below \[Z{{n}^{2+}}(aq)+2{{e}^{-}}Zn(s)-0.762\] \[C{{r}^{3+}}(aq)+3{{e}^{-}}Cr(s)-0.74\] \[2{{H}^{+}}(aq)+2{{e}^{-}}{{H}_{2}}(g)-0.00\] \[F{{e}^{3+}}(aq)+{{e}^{-}}F{{e}^{2+}}(aq)-0.77\] Which one of the following is the strongest reducing agent?

    A) \[Zn(s)\]                             

    B) \[Cr(s)\]

    C) \[{{H}_{2}}(g)\]

    D)        \[F{{e}^{2+}}(aq)\]

    Correct Answer: A

    Solution :

    The metals having higher negative value of standard reduction potential are placed above hydrogen in electrochemical series. The metals placed above hydrogen has a great tendency to donate electrons or to undergo oxidation. The metals having great power to undergo oxidation are strongest reducing agent. \[Zn\]has highest negative value of standard reduction potential. Therefore, it is the strongest reducing agent.


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