Manipal Engineering Manipal Engineering Solved Paper-2009

  • question_answer
    The moment of inertia of a circular ring of radius r and mass M about diameter is

    A)  \[\frac{2}{5}m{{r}^{2}}\]                             

    B) \[\frac{M{{r}^{2}}}{4}\]

    C)  \[\frac{M{{r}^{2}}}{2}\]      

    D)         \[\frac{M{{r}^{2}}}{12}\]

    Correct Answer: C

    Solution :

       Moment of inertia of a circular ring about diameter                 \[I=\frac{1}{2}M{{r}^{2}}\]          


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