A) \[PC{{l}_{3}}\]
B) \[PC{{l}_{5}}\]
C) \[SOC{{l}_{2}}\]in presence of pyridine
D) dry\[HCl\]in the presence of anhydrous\[ZnC{{l}_{2}}\]
Correct Answer: C
Solution :
The best method for the conversion of an alcohol into an alkyl chloride is by treating the alcohol with\[SOC{{l}_{2}}\]in the presence of pyridine. \[ROH+SOC{{l}_{2}}\xrightarrow{{}}RCl+HCl+S{{O}_{2}}\] The other products being gases escape leaving behind pure alkyl halide.
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